(5-5x)^2/(5+5x)^2=25

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Solution for (5-5x)^2/(5+5x)^2=25 equation:


D( x )

(5*x+5)^2 = 0

(5*x+5)^2 = 0

(5*x+5)^2 = 0

5*x+5 = 0 // - 5

5*x = -5 // : 5

x = -5/5

x = -1

x in (-oo:-1) U (-1:+oo)

((5-(5*x))^2)/((5*x+5)^2) = 25 // - 25

((5-(5*x))^2)/((5*x+5)^2)-25 = 0

((5-5*x)^2)/((5*x+5)^2)-25 = 0

((5-5*x)^2)/((5*x+5)^2)+(-25*(5*x+5)^2)/((5*x+5)^2) = 0

(5-5*x)^2-25*(5*x+5)^2 = 0

-600*x^2-1300*x-600 = 0

-600*x^2-1300*x-600 = 0

-100*(6*x^2+13*x+6) = 0

6*x^2+13*x+6 = 0

DELTA = 13^2-(4*6*6)

DELTA = 25

DELTA > 0

x = (25^(1/2)-13)/(2*6) or x = (-25^(1/2)-13)/(2*6)

x = -2/3 or x = -3/2

-100*(x+3/2)*(x+2/3) = 0

(-100*(x+3/2)*(x+2/3))/((5*x+5)^2) = 0

(-100*(x+3/2)*(x+2/3))/((5*x+5)^2) = 0 // * (5*x+5)^2

-100*(x+3/2)*(x+2/3) = 0

( x+2/3 )

x+2/3 = 0 // - 2/3

x = -2/3

( x+3/2 )

x+3/2 = 0 // - 3/2

x = -3/2

x in { -2/3, -3/2 }

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